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Routing: follow up scorpio810's review of #1245
- Rename the `near` lambda in Conductor::setPathPoints() to `isNear`: `near` and `far` are empty macros in the Windows headers (minwindef.h). - Reword the log when setPathPoints() refuses a route. "does not join the two terminals" named only one of its reasons; the router always returns the two terminals and at least one exit point, so a refusal means the route is not a run of horizontal and vertical segments between them. - README: running along another wire is penalised, not forbidden, so two wires can end up drawn on top of each other. Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
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@@ -1264,8 +1264,13 @@ QString QetScriptApi::applyRoute(Conductor *conductor, const QString &caller)
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return QStringLiteral("no-route");
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}
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if (!conductor->setPathPoints(route.points)) {
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log(QStringLiteral("qet.%1: the route found does not join the two terminals; "
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"the conductor keeps its path").arg(caller));
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// ConductorRouter always gives at least the two terminals and an
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// exit point between them, so this is a route that is not a run
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// of horizontal and vertical segments from one terminal to the
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// other -- a bug in the router, not something the folio did.
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log(QStringLiteral("qet.%1: the route found was refused (it must run in "
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"horizontal and vertical segments from one terminal to "
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"the other); the conductor keeps its path").arg(caller));
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return QStringLiteral("no-route");
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}
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return QStringLiteral("routed");
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